Hello！I wonder how to solve this problem：When I use “expression c2”,“expression c1”,I got the wrong number and the program does not report an error; But when I used “c1=0.000926;c2 = 2250;”,I got the right number and the program report an error, and display “Unable to perform assignment because value of type ‘cvx’ is not convertible to ‘double’.” in E(l,1)=c1*pow_pos(norm(v_opt(l)),3)+c2*inv_pos(v_opt(l));.

while 1

cvx_begin quiet

variable v_opt(length(t));

expression tempRate(48,1)

% expression c2

% expression c1

```
% f
for k=1:K
for n=1:N
pkn=sum(pSolution(n,1)); % Pk,n
end
tempRate(k,1)=log(alpha*(H^2+re(k))+pkn)/log(2);
end
f=sum(tempRate(:));
% g
for l=1:2
E(l,1)=c1*pow_pos(norm(v_opt(l)),3)+c2*inv_pos(v_opt(l));
end
g=sum(E(:));
M=f-elta(c)*g;
maximize M
subject to
```

cvx_end