Thanks in advance!

I have checked the function “x*(2^(1/x)-1)” is convex. I wonder how to express it in CVX to avoid the error “Cannot perform the operation: {real affine} .* {convex}”.

Are you @Wesen_Ning ? Your question looks very similar to How can cvx solve function like exp(x)*(exp(exp(-x))-1)? . To minimize confusion, please stick with one username if possible.

Hello，could you tell me how to solve the functions like x*(exp(1/x) - 1) In detail

I provided there the solution

variables x z

`{1,x,z} == exponential(1)`

Then x*(exp(1/x) - 1) can be formulated as z - x.

The exponential(1) constraint will constrain x > 0.

`2^(1/x)`

can be rewritten as `exp(log(2)/x)`

so just change

`{1,x,z} == exponential(1)`

to

`{log(2),x,z} == exponential(1)`

Thanks for your help and sorry to confuse you, I’m a new user. Does the exponential(1) constraint require x to be a scalar? If x is a vector, what’s the difference in expression?

maybe CVX will deal with vector in an elementwise manner, just one by one

I can’t find this function` exponential(1)`

in the CVX user’s guide. So, I’m so curious about the variables `z`

and `x`

means. Thanks!

It is documented as `exp_cone`

in http://cvxr.com/cvx/doc/funcref.html#sets , but you need to use the syntax with exponential(1) rather than `exp_cone`

.

If you have more than one of these constraints, specify them as individual scalar constraints inside a for loop.

Thanks, I find it in the CVX users’ guide.

Is there any method to represent this function, which is similar to the one above, but always displays real_ affine*log(convex).It’s really convex.

You posted this in a separate question?

Sorry, but reposting it here is very bad IMO because it is unrelated and wasting other peoples time.