How to express 1-F(x) using log_normcdf?

That is log of the complementary cumulative Normal distribution function. The sum of logs complicates things. But we can see that this is non-convex even if there is no sum (i.e., sum has one term).

Exponentiate (6) and then take log again, resulting in log_normcdf(u) <= log(1-exp(alpha)) . This is going in the wrong direction to be convex, because log_normcdf is concave.

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