i already know how to express

log(1+1/x) = log((1+x)/x) = -log(x/(1+x)) = -log(1 - 1/(1+x)) = -log(1 - inv_pos(1+x))

but how to how to espress log(1+1/x+1/y) in cvx

help help

i still donâ€™t know how to deal this problem after reading these approaches, would you do me a favor

I believe the first approach would be (using `zx`

and `zy`

in place of x_i and y_i)

```
variables x y t zx zy
t >= log_sum_exp([0 zx zy])
x >= exp(-zx)
y >= exp(-zy)
```

Then use `t`

in place of `log(1+1/x+1/y)`