Hi, I’m new to CVX Programming. Is my implemetation is correct?

Hi,
I am new to CVX. I have the following optimization problem, does it support in CVX?

Where p and t are L length known vectors; I need to estimate a and b.
Is following code is correct?
y=ln [p]; and A is a Lx2 matrix
cvx_begin quiet

variable x(2)

minimize( norm(A*x-y)), 2 ));

subject to
y=A*x;

``cvx_end``

Equality constraints should be written with == , not = . But it doesn’t make sense to have y == A*x as a constraint in this problem in which you are trying to minimize the norm (squared) of the deviation from that equality being satisfied.

``````cvx_begin
variables ln_a b
minimize(norm(log(p) - (ln_a - t*b)))
cvx_end``````

Thank you, Mark for your response. Is there is any specific reason to use log§ instead of ln§?. Also if I want to satisfied that a>0, a<=1 and b >0, can I use

cvx_begin
variables ln_a b
minimize(norm (log§ - (ln_a - t*b)))
subject to
a>0 && a<=1
b>0
cvx_end

There is no `ln` function in MATLAB. But `log` in MATLAB means natural logarithm.

`&&` is not allowed to be applied to cvx objects. However, you can use `0 <= a <= 1` . Or you can use two separate constraints.

Also note that `>` and `<` are interpreted as `>=` and `<=` . if you need strict inequality, you need to use non-strict inequality with a “buffer” larger than solver tolerance. For instance, `b >= 1e-5`.

You should carefully read CVX Users’ Guide http://cvxr.com/cvx/doc/