Hi,
I am using cvx on linux 64 bit.
I want to avoid printing logs on matlab console
where or how can i disable logs??
For example
When i run my optimization code , cvx prints the below following lines while solving the
optimization problem
How can I avoid printing these lines??
**SDPT3: Infeasible path-following algorithms
version predcorr gam expon scale_data
NT 1 0.000 1 0
it pstep dstep pinfeas dinfeas gap prim-obj dual-obj cputime
0|0.000|0.000|2.8e+00|3.3e+02|2.3e+11| 8.555857e+09 0.000000e+00| 0:0:00| chol 1 1
1|0.964|0.890|1.0e-01|3.6e+01|2.4e+10| 7.382990e+09 -3.417066e+06| 0:0:00| chol 1 1
2|1.000|0.880|9.3e-10|4.4e+00|8.9e+09| 6.548044e+09 -4.013488e+07| 0:0:00| chol 1 1
3|0.962|0.923|2.2e-10|3.4e-01|7.0e+08| 6.175386e+08 -8.759578e+06| 0:0:00| chol 1 1
4|0.887|0.911|1.3e-10|3.4e-02|1.2e+08| 1.068368e+08 -6.287747e+06| 0:0:00| chol 2 2
5|0.875|0.111|1.0e-09|3.7e-02|5.7e+07| 4.896137e+07 -5.817134e+06| 0:0:00| chol 2 2
6|1.000|0.403|1.7e-09|2.3e-02|3.0e+07| 2.498908e+07 -3.765194e+06| 0:0:00| chol 2 2
7|0.728|0.586|3.4e-09|9.8e-03|1.3e+07| 1.052412e+07 -2.170892e+06| 0:0:00| chol 2 2
8|1.000|0.232|2.9e-09|7.7e-03|6.3e+06| 4.309657e+06 -1.813565e+06| 0:0:00| chol 2 2
9|1.000|0.423|1.3e-08|4.5e-03|3.1e+06| 1.730164e+06 -1.304862e+06| 0:0:00| chol 2 2
10|1.000|0.448|5.1e-09|2.5e-03|1.3e+06| 3.181540e+05 -1.000261e+06| 0:0:00| chol 2 2
11|1.000|0.433|1.7e-08|1.5e-03|6.4e+05|-1.933911e+05 -8.178500e+05| 0:0:00| chol 2 2
12|1.000|0.450|1.1e-08|8.2e-04|2.8e+05|-4.312560e+05 -7.115868e+05| 0:0:00| chol 2 2
13|1.000|0.448|7.7e-09|4.6e-04|1.3e+05|-5.209355e+05 -6.521859e+05| 0:0:00| chol 2 2
14|1.000|0.491|1.0e-08|2.4e-04|5.6e+04|-5.617337e+05 -6.169893e+05| 0:0:00| chol 2 2
15|1.000|0.500|3.7e-09|1.2e-04|2.3e+04|-5.768618e+05 -5.998468e+05| 0:0:00| chol 2 2
16|1.000|0.484|6.1e-09|6.4e-05|9.9e+03|-5.827972e+05 -5.924973e+05| 0:0:00| chol 2 2
17|1.000|0.430|3.4e-09|3.7e-05|4.6e+03|-5.851534e+05 -5.896678e+05| 0:0:00| chol 2 2
18|1.000|0.452|3.4e-09|2.0e-05|2.1e+03|-5.861986e+05 -5.882293e+05| 0:0:00| chol 2 2
19|1.000|0.481|3.8e-09|1.1e-05|8.9e+02|-5.866546e+05 -5.875197e+05| 0:0:00| chol 2 2
20|0.734|0.176|8.5e-10|8.8e-06|7.0e+02|-5.867239e+05 -5.874085e+05| 0:0:00| chol 2 3
21|1.000|0.238|1.6e-09|6.7e-06|5.3e+02|-5.867707e+05 -5.872855e+05| 0:0:00| chol 2 2
22|0.823|0.548|6.9e-10|3.0e-06|2.4e+02|-5.868341e+05 -5.870650e+05| 0:0:00| chol 2 2
23|0.938|0.329|1.4e-09|2.0e-06|1.5e+02|-5.868613e+05 -5.870049e+05| 0:0:00| chol 2 3
24|1.000|0.267|2.9e-09|1.5e-06|1.1e+02|-5.868679e+05 -5.869727e+05| 0:0:00| chol 3 2
25|0.867|0.679|1.3e-09|4.8e-07|3.4e+01|-5.868779e+05 -5.869112e+05| 0:0:00| chol 2 2
26|0.925|0.614|2.7e-10|1.9e-07|1.2e+01|-5.868818e+05 -5.868936e+05| 0:0:00| chol 2 2
27|0.797|0.137|3.7e-10|1.6e-07|9.9e+00|-5.868826e+05 -5.868922e+05| 0:0:00| chol 2 3
28|1.000|0.246|1.1e-09|1.2e-07|7.1e+00|-5.868833e+05 -5.868902e+05| 0:0:00| chol 3 3
29|0.879|0.713|1.2e-09|3.5e-08|2.0e+00|-5.868839e+05 -5.868858e+05| 0:0:00| chol 2 3
30|1.000|0.070|1.1e-09|3.2e-08|1.8e+00|-5.868840e+05 -5.868857e+05| 0:0:00| chol 3 3
31|0.546|0.318|1.3e-09|2.2e-08|1.3e+00|-5.868840e+05 -5.868853e+05| 0:0:00| chol 3 4
32|0.918|0.229|4.8e-09|1.7e-08|9.7e-01|-5.868841e+05 -5.868851e+05| 0:0:00| chol 3 4
33|1.000|0.313|1.1e-08|1.2e-08|6.7e-01|-5.868842e+05 -5.868848e+05| 0:0:00| chol 4 4
34|1.000|0.692|3.7e-09|4.2e-09|1.9e-01|-5.868843e+05 -5.868845e+05| 0:0:00| chol 3 3
35|0.803|0.713|3.0e-09|1.9e-09|5.7e-02|-5.868843e+05 -5.868843e+05| 0:0:00| chol 3 3
36|0.776|0.221|9.2e-10|2.0e-09|4.2e-02|-5.868843e+05 -5.868843e+05| 0:0:00| chol 4 5
37|1.000|0.089|2.9e-08|2.0e-09|3.9e-02|-5.868843e+05 -5.868843e+05| 0:0:00| chol 5 5
38|0.860|0.839|5.3e-09|5.3e-10|7.2e-03|-5.868843e+05 -5.868843e+05| 0:0:01|
stop: max(relative gap, infeasibilities) < 1.49e-08
number of iterations = 38
primal objective value = -5.86884310e+05
dual objective value = -5.86884316e+05
gap := trace(XZ) = 7.18e-03
relative gap = 6.11e-09
actual relative gap = 4.83e-09
rel. primal infeas = 5.33e-09
rel. dual infeas = 5.35e-10
norm(X), norm(y), norm(Z) = 8.3e+05, 1.6e+01, 6.3e+01
norm(A), norm(b), norm© = 1.8e+04, 1.2e+06, 6.6e+01
Total CPU time (secs) = 0.51
CPU time per iteration = 0.01
termination code = 0
DIMACS: 5.3e-09 0.0e+00 4.3e-09 0.0e+00 4.8e-09 6.1e-09
Status: Solved**