Cvx form for R=a(log2(1+b*c/a*d))?

R=a(log2(1+b*c/a*d))
in above equation “a” and “b” are variables.
i write this equation in cvx but could not run.
is this equation ok for above?
-rel_entr((a*d),((a*d)+(b*c)))/log(2)
zaheer

If you tried putting in some “random” numbers for the variables, you would see that is not equivalent to your original formula.

-rel_entr(a,a+b*c/d)/log(2) or -1/d*rel_entr(a*d,a*d+b*c)/log(2) will work.