You can use my solution at How to write:log(1+1/x)<=y (divide the denominator in 1 + numerator/denominator, by the numerator, which puts it in the form log(1+1/x)) and divide the whole thing by log(2) to account for different base log.
You can use my solution at How to write:log(1+1/x)<=y (divide the denominator in 1 + numerator/denominator, by the numerator, which puts it in the form log(1+1/x)) and divide the whole thing by log(2) to account for different base log.