Log{convex} log(1+1/(1+x))

[Kirti_Kant_Sharma]

Thank you for quick reply. I also find on the forum a way to do this

Minimize log(1+1/x) where 0<x<inf

Sorry for the late answer. May be you can rewrite your problem in the following form minimize y such that log(1 + 1/x) \leq y which is equivalent to minimize y such that exp(-y) + exp(-y-log(x)) \leq 1 The following code is working at least cvx_begin variables x y minimize( y ) exp(-y) + exp(-y - log(x) ) <= 1 cvx_end