Hello , i had a problem with squaring a norm function
the function is
0.5*||(W.’)*sqrt(Rx)||^2 .
W is a 201 vector
Rx is a 2020 Matrix
i have tried
0.5*(square(norm(W.’*(sqrt(Rx)),2)
but there is a discipline error
Depending on the context, perhaps you don’t really need to square the norm.
If you do need to square the norm, you can use square_pos instead of square. Or if y is the argument of norm,. you can use y'*y.
The function at first was
0.5*W.'RxW + summation(eita+eitaDash)
The problem was that the part first part of the function had a problem as Rx turned the expresion to Convex/concave
I don’t understand. Has your problem been resolved or do you still have a problem? If the latter, you need to provide more information.
If
0.5*norm(W.’*(sqrt(Rx)),2)
is valid, then
0.5*(square_pos(norm(W.’*(sqrt(Rx)),2)
should be valid.
If 0.5*norm(W.’*(sqrt(Rx)),2)
is not valid
then you need to show your complete problem, so that we can understand what the argument of norm is.
It is valid and it worked , thank you