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Illegal operation: log( {convex} ) 1

Nonconvex
Apr 21, 2023
Z
ZBL
Apr 21, 2023 #1

Why is this part concave, but it is displayed as convex function in CVX?
The complete code is as follows(Seta is variable)
5

Z
ZBL
Apr 21, 2023 #2

4

M
Michal Adamaszek
Apr 21, 2023 #3

You have something that in one dimension looks essentially like \log(x^2+1) . That is neither convex nor concave.

1 reply
Z
ZBL
Apr 21, 2023 #4
Replying to #3

OK, thank you very much,l’ll check it again

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