How to address x^4/y in CVX, where y>=0?

Uncategorized
Mar 11, 2021
S
#1

By using Hessian matrix for x^4/y(y>=0), I confirm this matrix is semi-definite positve. But I don’t know which cvx expression can be used for x^4/y?

M
#2

For example t\geq z^2/y,\ z\geq x^2, that is quad_over_lin and square.

1 reply
E
#3
Replying to #2

Michal solution is the best.

However, alternatively

x \leq \mbox{geo_mean}(1,1,y,z)

should do the trick too.