Status failed in SDPT3.and status infeasible in SeDuMi and Mosek

hey guys
i’m trying to solve a problem about the "Convex programming approach to powered descent guidance for soft landing "
but the CVX returns Status:Failed always.
and I have tried use SeDuMi and Mosek to solve it, they both returned that:Infeasilbe.
so I want to know what’s the problem.Or how can I modify the model.
thanks!

startpos=[40000000;0;0;0;7350;0];
endpos=[-21082000;36515000;0;-2660;-1540;0];
J2=1.0826*10^(-9);Re=6378000;m0=1000;
Isp=300;ge=9.8;miu=398603*10^9;
Tm=100;
T=25000;Tc=50;
N=T/Tc;
z0=zeros(1,N+2);

 xr0= [startpos,[linspace(startpos(1), endpos(1), N); ...
	  linspace(startpos(2), endpos(2), N);linspace(startpos(3),endpos(3), N);
      linspace(startpos(4), endpos(4), N);linspace(startpos(5), endpos(5), N);
      linspace(startpos(6), endpos(6), N)],endpos];
xr=xr0;

  %cvx_solver sedumi or SDPT3 or Mosek
cvx_begin
%variable eta(N+2)
%variable tau(N+2)
variable x(7,N+2)
variable u(4,N+2)%
variable xdot(7,N+2)
expression us(N+2)


x(:,1)==[startpos;m0];x(:,2)==[startpos;m0];
x(1:6,N+2)==[endpos];x(1:6,N+2)==[endpos];
for t=2:N+1
 t1=xr(1,t);t2=xr(2,t);t3=xr(3,t);
I=eye(7,7);
r=(t1^2+t2^2+t3^2)^0.5;
Q=[miu/(r^3)+1.5*J2*(Re^2)/(r^5),0,0;
    0,miu/(r^3)+1.5*J2*(Re^2)/(r^5),0;
    0,0,miu/(r^3)+4.5*J2*(Re^2)/(r^5)];
A1=[zeros(3,3),eye(3),zeros(3,1);
    -Q,zeros(3,3),zeros(3,1);
    zeros(1,3),zeros(1,3),0];
B1=[zeros(3,3),zeros(3,1);eye(3),zeros(3,1);zeros(1,3),1/(Isp*ge)];
A=Tc*A1+I;
B=Tc*B1;


xdot(:,t)==(x(:,t)-x(:,t-1))/Tc;
xdot(:,t)-A*x(:,t)-B*u(:,t)==0;
z0(t)=log(m0-Tm/(Isp*ge)*(t-2)*Tc);
u(1,t)<=u(2,t);

u(2,:)>=0;
%us(t)=Tm*exp(-z0(t))*(1-x(7,t)-z0(t));
u(2,t)<=Tm;%*exp(-z0(t))*(1-x(7,t)-z0(t));
end
minimize sum(Tc*(x(2,:)))
cvx_end

Do you know that your problem should actually be feasible, at least if computed in exact arithmetic?

You seem to have some very large and and very small magnitude numbers, which could cause difficulties for solvers. Try to change the units so that numbers become closer to 1 in magnitude. I don’t know whether your result (infeasible declaration) will change when you do this, but it’s possible.

If you show the MOSEK solution summary it is quite easy to see how reliable the conclusion of MOSEK is.

yeah,it says “dual feasible”

You answer does not make sense. I suggest you paste in the whole summary as for instance shown in

http://docs.mosek.com/8.0/toolbox/tutorial-solution-analysis.html#the-solution-summary