As per one of the suggestions I gave you at Conversion to double from cvx is not possible , remove all instances of Rate and instead use
log(1+(p(i)*((distance(i,j)).^(-pathloss)))) >= Rate_min(i,j)
except that now that you have a denominator term on the left-hand side, move it to the right-hand side (as a multiplicative term), where it will be affine, and therefore accepted by CVX (you can put log(2) where you want).
Or you can change Rate(i,j) to not include the denominator, and proceed in the obvious manner based on the above to include the denominator term as a multiplicative term in the right-hand side of the inequality.