What if you write it as x-1000*log(1.01-0.01*inv_pos((x+1)))
. I’m not sure this is correct cvx syntax, I just mean transform the expression like this.
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What if you write it as x-1000*log(1.01-0.01*inv_pos((x+1)))
. I’m not sure this is correct cvx syntax, I just mean transform the expression like this.